The absolute world lightweight champion Devin Haney (28-0, 15 KOs) will meet in a rematch against ex-champion George Kambosos (20-1, 10 KOs).

This was announced by the promotion company Top Rank.

The second battle will take place on October 15 in Melbourne, Australia..

Note that the former world lightweight champion Vasily Lomachenko (16-2, 11 KOs) wants to meet the winner of this fight..

Earlier it became known when Lomachenko will hold his next fight and who will be his opponent.

Lomachenko has 16 wins (11 by knockout) and 2 losses in the professional ring.

In the last fight, on the night of December 12, Vasily defeated the messenger Richard Commey and won the WBO Intercontinental Champion belt.;

As for Haney, he has 28 wins (15 by knockout) in 28 fights.;

In the fight for the title of absolute world champion, Haney defeated Australian George Kambosos by unanimous decision.. George activated the option of a rematch with Haney. Earlier it was reported that the second fight between Haney and Kambosos will take place on October 15 in Melbourne..